Maths |
Complex Numbers |
| Complex Numbers |
| Note: Some textbooks use the letter j to represent the imaginary part of a complex number. I have used the more universal i throughout. |
| A complex number, z, is of the form: |
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z = x + iy |
| or, using polar coordinates : |
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z = [ r , θ ] |
| where x and y are real numbers and: |
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i = - 1 |
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i 2 = - 1 |
| The modulus of a complex number is: |
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| z | = x 2 + y 2 |
| The argument of a complex number is: |
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arg ( z ) = tan - 1 ( y x ) |
| The conjugate of a complex number is: |
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z * = x − iy |
| In the following lines: |
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z 1 = a + ib |
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z 2 = c + id |
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z 1 + z 2 = ( a + bi ) + ( c + di )   = ( a + c ) + ( b + d ) i |
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z 1 − z 2 = ( a + bi ) − ( c + di )   = ( a − c ) + ( b − d ) i |
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z 1 z 2 = ac + adi + bci + bdi 2                    = ( ac − bd ) + ( ad + bc ) i |
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z 1 z 2 = a + bi c + di             = ( a + bi ) ( c - di ) ( c + di ) ( c - di )             = ac ⁢ - adi + bci - bdi 2 c 2 - d 2 i 2               = ac + bd + ( bc - ad ) i c 2 + d 2               = ac + bd c 2 + d 2 + ( bc - ad c 2 + d 2 ) i |
| For z = x + iy and where y is measured in radians: |
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e z = e x ( cos ⁢       y ⁢ + i ⁢ sin ⁢     y ) |
When θ is measured in radians:
The exponential form of a complex number: |
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[ r , θ ] = r ⁢ e iθ |
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e x + iy = e x ( cos ⁢   ⁢ y + i ⁢ sin ⁢   y ) |
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a z = e zlna , a ∈ ℝ + |
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e z 1 × e z 2 = e z 1 + z 2 |
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e z 1 e z 2 = e z 1 − z 2 |
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ln ( r ⁢ e iθ ) = ln ⁢   r + i ( θ + 2 n ⁢ θ ) , n ⁢ ∈ ℤ |
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a x + iy = a x ( cos ( y ⁢ ln ⁢ a ) + i ⁢ sin ( y ⁢ ln ⁢ a ) ) |
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e iz = cos ⁢   z + i ⁢ sin ⁢ z |
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sin ⁢   z = e iz − e − iz 2 i |
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cos ⁢   z = e iz + e − iz 2 |
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sec ⁢   z = 1 cos ⁢   z = 2 e iz + e − iz |
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csc ⁢   z = 1 sin ⁢   z = 2 i e iz − e − iz |
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tan ⁢   z = sin ⁢   z coz ⁢   z = e iz − e − iz i ( e iz + e − iz ) |
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cot ⁢   z ⁢ = cos ⁢   z sin ⁢   z = i ( e iz + e − iz ) e iz − e − iz |
| Complex Trigonometric Function Properties: |
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sin 2 z + cos 2 z = 1 |
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1 + tan 2 z = sec 2 z |
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1 + cot 2 z = csc 2 z |
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sin ( - z ) = - sin ⁢   z |
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cos ( - z ) = cos ⁢   z |
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tan ( - z ) = - tan ⁢   z |
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sin   ( z 1 ± z 2 ) = sin ⁢     z 1 ⁢   cos ⁢     z 2 ± cos ⁢     z 1 sin ⁢     z 2 |
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cos ( z 1 ± z 2 ) = cos ⁢     z 1 ⁢     co s ⁢     z 2 ∓ sin ⁢     z 1 ⁢   sin ⁢     z 2 |
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tan ( z 1 ± z 2 ) = tan ⁢     z 1 ± tan ⁢     z 2 1 ∓ tan ⁢     z 1 ⁢   tan ⁢     z 2 |
| Complex Hyperbolic Functions: |
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sinh ⁢     z = e z - e - z 2 |
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cosh ⁢     z = e z + e - z 2 |
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sech ⁢     z = 1 cosh ⁢       z = 2 e z + e -     z |
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csch ⁢     z = 1 sinh ⁢       z = 2 e z - e -     z |
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tanh ⁢     z = sinh ⁢     z cosh ⁢       z = e z - e -     z e z + e -     z |
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coth ⁢     z = cosh ⁢     z sinh ⁢       z = e z + e -     z e z - e -     z |
| Complex Hyperbolic Properties: |
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cosh 2 ⁢   ⁢ z − sinh 2 ⁢   z = 1 |
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1 − tanh 2 ⁢   z = sech 2 ⁢   z |
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coth 2 ⁢   z − 1 = csch 2 ⁢   z |
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sinh ( − z ) = − sinh ⁢     z |
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cosh ( − z ) = cosh ⁢     z |
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tanh ( − z ) = − tanh ⁢   z |
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sinh ( z 1 ± z 2 ) = sinh ⁢   z 1 cosh ⁢   z 2 ± cosh ⁢   z 1 sinh ⁢   z 2 |
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cosh ⁢ ( z 1 ± z 2 ) = cosh ⁢   z 1 cosh ⁢   z 2 ± sinh ⁢   z 1 sinh ⁢   z 2 |
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tanh ( z 1 ± z 2 ) = tanh ⁢     z 1 ± tanh ⁢     z 2 1 ± tanh ⁢     z 1 ⁢   tanh ⁢     z 2 |
| Complex Trigonometric and Hyperbolic Function Relations: |
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sin ⁢   iz = i ⁢   sinh ⁢   z |
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cos ⁢   iz = cosh ⁢   z |
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tan ⁢   iz = i ⁢   tanh ⁢   z |
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sinh ⁢   iz = i ⁢   sin ⁢   z |
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cosh ⁢   iz = cos ⁢   z |
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tanh ⁢   iz = i ⁢   tan ⁢   z |
| Complex Inverse Trigonometric Functions: |
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sin − 1 z = 1 i ln ( iz + 1 − z 2 + 2 k ⁢ π ⁢ i ) , k ⁢   ∈     ℤ |
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cos − 1 z = 1 i ln ( z + z 2 - 1 + 2 k ⁢ π ⁢ i ) , k ⁢   ∈     ℤ |
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csc − 1 z = 1 i ln ( i + z 2 - 1 z + 2 k ⁢ π ⁢ i ) , k ⁢   ∈     ℤ |
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sec − 1 z = 1 i ln ( 1 + 1 − z 2 z + 2 k ⁢ π ⁢ i ) , k ⁢   ∈     ℤ |
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tan − 1 z = 1 2 i ln ( 1 + iz 1 − iz + 2 k ⁢ π ⁢ i ) , k ⁢   ∈     ℤ |
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cot − 1 z = 1 2 i ln ( z + i z − i + 2 k ⁢ π ⁢ i ) , k ⁢   ∈     ℤ |
| Complex Inverse Hyperbolic Functions: |
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sinh − 1 z = ln ( z + z 2 + 1 + 2 k ⁢ π ⁢ i ) , k ⁢   ∈     ℤ |
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cosh − 1 z = ln ( z + z 2 − 1 + 2 k ⁢ π ⁢ i ) , k ⁢   ∈     ℤ |
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csch − 1 z = ln ( 1 + z 2 + 1 z + 2 k ⁢ π ⁢ i ) , k ⁢   ∈     ℤ |
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sech − 1 z = ln ( 1 + 1 − z 2 z + 2 k ⁢ π ⁢ i ) , k ⁢   ∈     ℤ |
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tanh − 1 z = 1 2 ln ( 1 + z 1 − z + 2 k ⁢ π ⁢ i ) , k ⁢   ∈     ℤ |
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coth − 1 z = 1 2 ln ( z + 1 z − 1 + 2 k ⁢ π ⁢ i ) , k ⁢   ∈     ℤ |